C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t soi c\u1ea7u tr\u00fang 1 con l\u00f4<\/figcaption><\/figure>\nX\u00e1c su\u1ea5t soi c\u1ea7u tr\u00fang 1 con l\u00f4<\/h2>\n
Ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u<\/strong> n\u00e0y d\u1ef1a v\u00e0o c\u00e1c y\u1ebfu t\u1ed1 nh\u01b0 x\u00e1c su\u1ea5t, quy lu\u1eadt s\u1ed1 Pi v\u00e0 tr\u1ef1c gi\u00e1c. C\u00e1ch t\u00ednh n\u00e0y kh\u00f4ng t\u00ednh l\u00e0 tr\u00fang 2 s\u1ed1, hay 3 s\u1ed1, m\u00e0 n\u00f3 nh\u1ea5n m\u1ea1nh v\u00e0o duy nh\u1ea5t m\u1ed9t con s\u1ed1.<\/p>\nM\u1ecdi ng\u01b0\u1eddi \u0111\u1ec1u bi\u1ebft x\u00e1c su\u1ea5t t\u1ed1i \u0111a l\u00e0 100%. Nh\u01b0ng trong th\u1ef1c t\u1ebf r\u1ea5t \u00edt khi ch\u00fang ta \u0111\u1ea1t \u0111\u01b0\u1ee3c con s\u1ed1 l\u00fd t\u01b0\u1edfng \u0111\u00f3. X\u00e1c su\u1ea5t tr\u00fang l\u00f4 \u0111\u1ec1 l\u00e0 50 l\u00e0 50\/50. Ch\u1ec9 c\u00f3 th\u1eafng ho\u1eb7c l\u00e0 thua. C\u0169ng gi\u1ed1ng nh\u01b0 vi\u1ec7c ch\u01a1i t\u00e0i x\u1ec9u ho\u1eb7c x\u00f3c d\u0129a ho\u1eb7c ch\u01a1i b\u00e0n quay Roulette t\u1ef7 l\u1ec7 50% \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng khi m\u00e0 ch\u00fang ta c\u00f3 2 l\u1ef1a ch\u1ecdn l\u00e0 ch\u1eb5n, l\u1ebb (t\u00e0i x\u1ec9u) ho\u1eb7c tr\u1eafng \u0111\u1ecf (x\u00f3c d\u0129a) ho\u1eb7c \u0111\u1ecf.<\/p>\n
C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t soi c\u1ea7u tr\u00fang 1 con l\u00f4<\/h2>\n
\u0110\u1ec3 t\u00ednh x\u00e1c su\u1ea5t soi c\u1ea7u tr\u00fang 1 con l\u00f4 th\u00ec tr\u01b0\u1edbc ti\u00ean b\u1ea1n c\u1ea7n t\u00ednh x\u00e1c su\u1ea5t tr\u01b0\u1ee3t. T\u00ednh tr\u01b0\u1ee3t bao gi\u1edd c\u0169ng d\u1ec5 h\u01a1n t\u00ednh x\u00e1c su\u1ea5t th\u1eafng.
\nT\u1ef7 l\u1ec7 th\u1eafng t\u1ed1i \u0111a 100% (t\u00ednh l\u00e0 1) cho 27 l\u00f4 mi\u1ec1n B\u1eafc g\u1ed3m 100 s\u1ed1 t\u1eeb 00 \u0111\u1ebfn 99
\nT\u1ef7 l\u1ec7 thua khi b\u1ea1n \u0111\u00e1nh 1 con l\u00f4 99% (\u0111\u00e1nh 1 con)<\/p>\n
C\u1ee5 th\u1ec3 c\u00e1ch t\u00ednh nh\u01b0 sau<\/h3>\n
T\u1ea1ch 1 l\u00f4 l\u00e0 99%
\nT\u1ea1ch 2 l\u00f4 l\u00e0 99% * 99%
\nT\u1ea1ch 3 l\u00f4 l\u00e0 99% * 99% * 99%
\n\u2026
\nT\u1ea1ch 27 l\u00f4 l\u00e0 99% ^ 27 (99% nh\u00e2n v\u1edbi 27 l\u1ea7n ch\u00ednh n\u00f3)
\nB\u1ea1n ph\u1ea3i t\u1ea1ch h\u1ebft 27 con l\u00f4 th\u00ec t\u1ef7 l\u1ec7 99% m\u1edbi x\u1ea3y ra cho n\u00ean t\u1ef7 l\u1ec7 tr\u00fang 1 con l\u00f4 \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 sau:
\n[1 \u2013 (99% ^ 27)] * 100 ~ 23,7%
\nC\u1ee9 nh\u01b0 v\u1eady b\u1ea1n ti\u1ebfp t\u1ee5c t\u00ednh
\n2 con l\u00f4 l\u00e0 [1 \u2013 (98% ^ 27)] * 100 ~ 42%
\n3 con l\u00f4 l\u00e0 [1 \u2013 (97% ^ 27)] * 100 ~ 56%
\n4 con l\u00f4 l\u00e0 [1 \u2013 (96% ^ 27)] * 100 ~ 67%<\/p>\n
C\u00f4ng th\u1ee9c t\u1ed5ng<\/h3>\n
[1 \u2013 [{100-n}% ^ 27)] * 100
\nv\u1edbi n l\u00e0 s\u1ed1 con l\u00f4 b\u1ea1n \u0111\u00e1nh
\nC\u00f4ng th\u1ee9c tr\u00ean s\u1ebd l\u00e0 l\u00fd t\u01b0\u1edfng cho b\u1ea1n v\u00ec l\u00f4 ch\u1ec9 x\u1ed5 27 gi\u1ea3i v\u00e0 c\u00f3 th\u1ec3 c\u00f3 s\u1ed1 tr\u00f9ng. N\u00ean n\u1ebfu nh\u01b0 b\u1ea1n c\u00f3 th\u1ec3 th\u1ed1ng k\u00ea \u0111\u01b0\u1ee3c t\u1ea5t c\u1ea3 c\u00e1c con s\u1ed1 hay ra v\u00e0 kho\u1ea3ng s\u1ed1 hay ra th\u00ec b\u1ea1n ho\u00e0n to\u00e0n c\u00f3 th\u1ec3 \u0103n l\u00f4.<\/p>\n
K\u1ebft<\/h2>\n
Tr\u00ean \u0111\u00e2y l\u00e0 c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t soi c\u1ea7u xsmb<\/a>, xsmn, xsmt<\/strong> tr\u00fang 1 con l\u00f4 v\u00f4 c\u00f9ng hi\u1ec7u qu\u1ea3 \u0111\u01b0\u1ee3c anh em c\u1ea3 3 mi\u1ec1n tin t\u01b0\u1edfng. Trong th\u1ef1c t\u1ebf \u0111\u00e3 ch\u1ee9ng minh, \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p mang l\u1ea1i l\u1ee3i \u00edch kinh t\u1ebf cao cho ng\u01b0\u1eddi ch\u01a1i.
\nCh\u00fac c\u00e1c b\u1ea1n th\u00e0nh c\u00f4ng!<\/p>\n