D\u00f9ng \u0111\u1ea7u 0 \u0111\u00edt 0 \u0111\u1ec3 soi c\u1ea7u th\u1ee9 b\u1ea3y<\/figcaption><\/figure>\nD\u1ea5u hi\u1ec7u \u0111\u1ec3 b\u1eaft theo ph\u01b0\u01a1ng ph\u00e1p n\u00e0y l\u00e0 t\u00ecm ki\u1ebfm xem, trong k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ng\u00e0y th\u1ee9 7 c\u00f3 con s\u1ed1 0 n\u1eb1m ch\u00ednh gi\u1eefa hay kh\u00f4ng. N\u1ebfu tr\u01b0\u1eddng h\u1ee3p \u0111\u00f3 x\u1ea3y ra th\u00ec r\u1ea5t c\u00f3 th\u1ec3 trong 3 ng\u00e0y ti\u1ebfp theo l\u00f4 s\u1ebd v\u1ec1 d\u1ea1ng \u0111\u1ea7u 0 \u0111\u00edt 0.<\/p>\n
V\u00ed d\u1ee5 ki\u1ec3m ch\u1ee9ng:<\/b><\/p>\n
Ki\u1ec3m ch\u1ee9ng trong ng\u00e0y 01\/05 c\u00f3 s\u1ed1 0 n\u1eb1m ch\u00ednh gi\u1eefa k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1, c\u1ee5 th\u1ec3 s\u1ed1 c\u00f4ng b\u1ed1 l\u00e0 69023. V\u00e0 ngay l\u1eadp t\u1ee9c, ng\u00e0y h\u00f4m sau \u0111\u1ec1 v\u1ec1 con 05 \u2013 \u0111\u1ea7u 0.<\/p>\n
B\u1eaft T\u1ed5ng \u0110\u1ec1 \u0110\u1ec3 Soi C\u1ea7u Th\u1ee9 B\u1ea3y Ch\u00ednh X\u00e1c:<\/b><\/h2>\n
T\u1ed5ng \u0111\u1ec1 l\u00e0 m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u ph\u1ed5 bi\u1ebfn, \u0111\u01b0\u1ee3c nhi\u1ec1u ng\u01b0\u1eddi \u01b0a chu\u1ed9ng nh\u1edd t\u00ednh ch\u00ednh x\u00e1c, hi\u1ec7u qu\u1ea3 cao c\u1ee7a n\u00f3. Th\u1eadm ch\u00ed, \u0111\u00e2y c\u00f2n \u0111\u01b0\u1ee3c \u0111\u00e1nh gi\u00e1 l\u00e0 c\u00e1ch soi c\u1ea7u th\u1ee9 b\u1ea3y <\/b>c\u00f3 t\u1ef7 l\u1ec7 v\u1ec1 gi\u1ea3i cao nh\u1ea5t mi\u1ec1n B\u1eafc.<\/p>\n
C\u00e1ch th\u1ef1c hi\u1ec7n r\u1ea5t \u0111\u01a1n gi\u1ea3n. Trong k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ng\u00e0y th\u1ee9 7, b\u1ea1n h\u00e3y theo d\u00f5i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t sau \u0111\u00f3 c\u1ed9ng t\u1ed5ng to\u00e0n b\u1ed9 5 con s\u1ed1 \u0111\u00f3 l\u1ea1i v\u1edbi nhau. K\u1ebft qu\u1ea3 t\u00ecm \u0111\u01b0\u1ee3c s\u1ebd l\u00e0 con l\u00f4 \u0111\u1eb9p d\u00f9ng \u0111\u1ec3 \u0111\u00e1nh cho h\u00f4m sau.<\/p>\n
V\u00ed d\u1ee5:<\/b> gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y 4\/10\/2024 b\u00e1o c\u00e1c s\u1ed1 78011, t\u1ed5ng 5 con s\u1ed1 n\u00e0y l\u1ea1i l\u00e0: 7 + 8 + 0 + 1 + 1 = 17. V\u00e0 ch\u00ednh x\u00e1c ng\u00e0y h\u00f4m sau ai \u0111\u00e1nh con s\u1ed1 17 \u0111\u1ec1u \u0103n l\u1edbn.<\/p>\n
L\u01b0u \u00fd:<\/b> Con l\u00f4 t\u00ecm ki\u1ebfm \u0111\u01b0\u1ee3c \u1edf ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u1ec9 n\u00ean nu\u00f4i trong t\u1ed1i \u0111a 5 \u2013 7 ng\u00e0y. N\u1ebfu sau th\u1eddi h\u1ea1n 7 ng\u00e0y m\u00e0 n\u00f3 v\u1eabn ch\u01b0a ra th\u00ec n\u00ean b\u1ecf, t\u00ecm ki\u1ebfm con kh\u00e1c, tr\u00e1nh l\u1ed7 nhi\u1ec1u.<\/p>\nSoi C\u1ea7u Th\u1ee9 B\u1ea3y Ch\u00ednh X\u00e1c B\u1eb1ng Ph\u01b0\u01a1ng Ph\u00e1p B\u1eaft \u0110\u1ec1 Chu\u1ea9n:<\/b><\/h2>\n
\u0110\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u th\u1ee9 b\u1ea3y <\/b>l\u1ea5y k\u1ebft qu\u1ea3 c\u1ee7a 2 ng\u00e0y \u0111\u1ea7u tu\u1ea7n.<\/p>\n
C\u1ee5 th\u1ec3, th\u1ed1ng k\u00ea k\u1ebft qu\u1ea3 l\u00f4 \u0111\u1ec1 c\u1ee7a ng\u00e0y th\u1ee9 2, th\u1ee9 3. Trong \u0111\u00f3, ch\u00fa \u00fd t\u1edbi 2 con s\u1ed1 c\u1ee7a l\u00f4 \u0111\u1ea7u ti\u00ean trong c\u00e1c ng\u00e0y \u0111\u00f3. C\u1ed9ng ch\u00fang l\u1ea1i v\u1edbi nhau ra t\u1ed5ng. V\u00e0 \u0111\u00f3 ch\u00ednh l\u00e0 con s\u1ed1 \u0111\u1eb9p \u0111\u1ec3 \u0111\u00e1nh trong th\u1ee9 7.<\/p>\n